Calculate the enthalpy change for the reaction 2 hcl → h2 + cl2 1. + 184 kj/mol of rxn 2. + 428 kj/mol of rxn 3. 0 kj/mol of rxn 4. - 184 kj/mol of rxn 5. - 244 kj/mol of rxn

Below is the list of enthalpies of formation of the compounds involved in the chemical reaction.

HCl: - 92.3 kJ/mol

H2: 0

Cl2: 0

Both H2 and Cl2 do not have enthaply of formation because they are pure substances.

Since, in the reaction there are 2 moles of HCl,

Enthalphy of formation = enthalpy of products - enthalphy of reactant/s

= 0 - (-92.3) (2) = + 184.6 kJ

Hence, the answer is the first choice.