Determine the concentrations of hg22 and cl - in a saturated solution of hg2cl2 in

a. pure water (assume μ = 0).

To solve this, we need the solubility constant for Hg2Cl2, which is:

Ksp = 1.4 x 10^-18

The ionic formula would be:

Hg2Cl2 (s) - - - > Hg2 2 + (aq) + 2Cl - (aq)

Therefore the total amounts of ions produced = x M Hg2 2 + and 2x M Cl-

The formula for Ksp in this case is:

Ksp = [Hg2 2+] [Cl-]^2

1.4 x 10^-18 = (x) * (2x) ^2

1.4 x 10^-18 = 4x^3

x = 7.0 x 10^-7 M = [Hg2 2+]

2x = 14 x 10^-7 M = [Cl-]