How much oxygen gas can be produced through the decomposition of potassium chlorate (KClO3) if 194.7 g of potassium chlorate is heated and fully decomposes? The equation for this reaction must be balanced first. KClO3 (s) - > KCl (s) + O2 (g) A. 194.70 grams

B. 76.26 grams

C. 2.47 grams

D. 2.38 grams

The balanced chemical reaction is expressed as:

2KClO3 (s) - > 2KCl (s) + 3O2 (g)

To determine the amount of oxygen that is being produced in the reaction from the given amount of the starting material, we need the balanced chemical reaction to relate the substances and the molar masses of the substances involved. The molar mass of KClO3 is 122.55 g/mol and O2 is 32 g/mol. We do as follows:

194.7 g KClO3 (1 mol KClO3 / 122.55 g KClO3) (3 mol O2 / 2 mol KClO3) (32 g O2 / 1 mol O2) = 76.26 g O2

Therefore, 76.26 g of oxygen gas is being produced from 194.7 g of potassium chlorate.