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Find the temperature from 150ml cylinder containing 0.75 moles gas at 153kpa.

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  1. Today, 09:24
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    To find the temperature in the problem, we apply the ideal gas law, PV=nRT where R=8.314 Pam3/mol K. Substituting the given, T = 153,000 Pa*1.5x10^-4 m3 / [ (0.75 mol) (8.314 Pam3/mol K) ]. The temperature is equal to 3.68 kelvin.
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