Ask Question
3 June, 21:36

The value for Kw is 1.0 x 10-14 at 298K, but this value is temperature dependent. Given what you know about Kw and acid/base chemistry, what will the pH of water be at 283K if the value for Kw is 0.29 x 10-14? Is this solution acidic, basic, or neutral? A. pH = 7.26, acidicB. pH = 7.26, neutralC. pH = 7.00, neutralD. pH = 14.54, basicE. pH = 7.26, basic

+1
Answers (1)
  1. 4 June, 01:01
    0
    Water is a llittle basic solution at 283K, pH = 7.26

    Option E.

    Explanation:

    The water equilibrium is this:

    2H₂O → H₃O⁺ + OH⁻ Kw = 1x10⁻¹⁴

    At 283K, Kw = 0.29x10⁻¹⁴

    [H₃O⁺]. [OH⁻] = 0.29x10⁻¹⁴

    √0.29x10⁻¹⁴ = [H₃O⁺] → 5.38x10⁻⁸

    √0.29x10⁻¹⁴ = [OH⁻]

    - log [H₃O⁺] = pH

    - log 5.38x10⁻⁸ = 7.26

    pH > 7 = Basic

    pH < 7 = Acidic

    pH = 7 → Neutral
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The value for Kw is 1.0 x 10-14 at 298K, but this value is temperature dependent. Given what you know about Kw and acid/base chemistry, ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers