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1 September, 10:41

calculate the final temperature of 202 mL of water initially at 32 degrees celsius upon absorption of 19 kJ of heat

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  1. 1 September, 10:54
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    The Final Temperature of water = 54.48°C.

    Explanation:

    Given,

    Volume of water = 202 mL.

    Initial Temperature T₁ = 32°C

    Heat energy absorbed = 19 kJ = 19000 Joules

    Final Temperature T₂ = ?

    Final temperature can be calculated using the formula,

    Q = (mass) (ΔT) (Cp)

    Here ΔT = T₂ - T₁

    Cp = specific heat of water = 4.184 J/g°C.

    For finding the mass, we use the formula,

    Density = Mass/Volume

    Since, Density of water = 1 g/mL.

    Mass of water = 202 grams.

    Now Substituting all values in the formula Q = (mass) (ΔT) (Cp)

    19000 = (202) (T₂ - T₁) (4.184)

    Solving, we get,

    (T₂ - T₁) = 22.48°C

    Therefore, T₂ = 22.48°C + 32°C = 54.48°C.

    Therefore, Final Temperature of water = 54.48°C.
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