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6 March, 15:57

How many molecules are present in a drop of ethanol, c2h5oh, of mass 2.3*10^-2.3g? (NA=6.0*10^23mol^-1)

explain why

a) 3.0*10^19

b) 3.0*10^20

c) 6.0*10^20

d) 6.0*10^26

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Answers (1)
  1. 6 March, 18:47
    0
    3.0 * 10²⁰ molecules

    Explanation:

    Given dа ta:

    Mass of ethanol = 2.3 * 10⁻²°³ g

    Number of molecules = ?

    Solution:

    Number of moles of ethanol:

    Number of moles = mass / molar mass

    Number of moles = 2.3 * 10⁻²°³ g / 46.07 g/mol

    Number of moles = 0.05 * 10⁻²°³ mol

    Number of molecules:

    One mole = 6.022 * 10²³ molecules

    0.05 * 10⁻²°³ mol * 6.022 * 10²³ molecules / 1 mol

    0.30 * 10²⁰°⁷ molecules

    3.0 * 10¹⁹°⁷ molecules which is almost equal to 3.0 * 10²⁰ molecules.
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