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29 August, 14:22

What is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of water from 22°C to 66°C?

(1) 9100 J

(2) 4600 J

(3) 1400 J

(4) 2300 J

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Answers (2)
  1. 29 August, 15:28
    0
    (1) 9100 J.

    Explanation:

    This would be an increase of 44 degees C and the specific heat of water is 4.186 joules / /g/degree C.

    So it is 49.5 * 4.186 * 44

    = 9100J.
  2. 29 August, 15:30
    0
    The answer to your question is: (1) 9100 J

    Explanation:

    Data

    Q = ? J

    mass = 49.5 g = 0.0495 kg

    T1 = 22°C

    T2 = 66°C

    Cp = 4.18 J/Kg°C

    Formula

    Q = mCpΔT

    Substitution

    Q = (4.95) (4.18) (66 - 22)

    Q = 9104 J
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