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28 March, 07:32

How many milliliters of 0.2 M NaOH are required to exactly neutralize 40 milliliters of 0.1 M HCl?

A) 10

B) 20

C) 40

D) 80

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Answers (1)
  1. 28 March, 09:37
    0
    Option B. 20mL

    Explanation:

    Step 1:

    Data obtained from the question.

    Volume of base (Vb) = ... ?

    Molarity of base (Mb) = 0.2M

    Volume of acid (Va) = 40mL

    Molarity of acid (Ma) = 0.1M

    Step 2:

    The balanced equation for the reaction.

    HCl + NaOH - > NaCl + H2O

    From the balanced equation above, the following were obtained:

    Mole ratio of the acid (nA) = 1

    Mole ratio of the base (nB) = 1

    Step 3:

    Determination of the volume of base, NaOH needed for the reaction. This is illustrated below:

    MaVa/MbVb = nA/nB

    0.1 x 40 / 0.2 x Vb = 1

    Cross multiply

    0.2 x Vb = 0.1 x 40

    Divide both side by 0.2

    Vb = 0.1 x 40 / 0.2

    Vb = 20mL

    Therefore, the volume of the base is 20mL.
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