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19 November, 03:16

At a certain temperature, 0.900 mol of SO3 is placed in a 2.00-L container.

2SO3 (g) 2SO2 (g) + O2 (g)

At equilibrium, 0.130 mol of O2 is present. Calculate Kc.

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  1. 19 November, 03:28
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    Kc = 2.34 mol*L

    Explanation:

    The calculation of the Kc of a reaction is performed using the values of the concentrations of the participants in the equilibrium.

    A + B ⇄ C + D

    Kc = [C] * [D] / [A] * [B]

    According to the reaction

    Kc = [SO2]^2 * [O2]^2 / [SO3]^2

    Knowing the 0.900 mol of SO3 is placed in a 2.00-L it means we have a 0.450 mol/L of SO3

    0.450 - -> 0 + 0 (Beginning of the reaction)

    0.260 - -> 0.260 + 0.130 (During the reaction)

    0.190 - -> 0.260 + 0.130 (Equilibrium of the reaction)

    Kc = [0.260]^2 + [0.130]^2 / [0.190]^2

    Kc = 2.34 mol*L
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