A sample of gas has a volume of 1.20 L at standard conditions. Find its volume at 35.0 oC and 900 torr. (R = 62.4 L torr/K * mol)

Group of answer choices

A. 1.14 L

B. 2.52 L

C. 0.980 mL

D. 3.92 mL

Option A. 1.14L

Explanation:

Data obtained from the question include:

V1 = 1.20 L

P1 = at stp = 760torr

T1 = at stp = 273K

P2 = 900torr

T2 = 35°C = 35 + 273 = 308K

V2 = ?

Using P1V1/T1 = P2V2/T2, we can obtain the new volume as follows:

P1V1/T1 = P2V2/T2

(760 x 1.2) / 273 = (900 x V2) / 308

Cross multiply to express in linear form

273 x 900 x V2 = 760 x 1.2 x 308

Divide both side by 273 x 900

V2 = (760 x 1.2 x 308) / (273 x 900)

V2 = 1.14L

Answer: 1.14L

Explanation:

P1V1/T1=P2V2/T2

P1=760torr

V=1.20L

T1=373K

P2=900torr

V2=?

T2=308K

P1V1T2=P2V2T1

V2 = P1V1T2/P2T1

V2=760*1.20*308/900*273

V2=280896/245700

V2=1.14L