How many Grams of C₆H₆ must decompose according to the following chemical equation to transfer 430kj of heat?

C₆H₆ (l) → 3 C₂H₂ (g) ∆H = 630 kj

53.3 g C6H6

Explanation:

C₆H₆ (l) → 3 C₂H₂ (g) ∆H = 630 kj

From reaction 1 mol ∆H = 630 kj

Given x mol ∆H = 430 kj

x = (1 mol*430 kJ) / 630 kJ = 0.683 mol C6H6

M (C6H6) = 12*6 + 1*6 = 78 g/mol

0.683 mol C6H6 * 78 g/mol ≈ 53.3 g