Consider the following reaction: 2HI (aq) + Ba (OH) 2 (aq) → 2H2O (l) + BaI2 (aq) Enter the complete ionic equation for this reaction. Express your answer as a complete ionic equation. Identify all of the phases in your answer

2 HI (aq) + Ba²⁺ (aq) + 2 OH⁻ (aq) → 2 H₂O (l) + Ba²⁺ (aq) + 2I⁻ (aq)

Explanation:

Let's consider the following balanced molecular equation.

2 HI (aq) + Ba (OH) ₂ (aq) → 2 H₂O (l) + BaI₂ (aq)

In the complete ionic equation we include all the ions and the species that do not dissociate in water. HI is a weak electrolyte so it exists mostly in the molecular form. H₂O has a very low equilibrium constant (Kw = 10⁻¹⁴) si it exists mainly in the molecular form.

2 HI (aq) + Ba²⁺ (aq) + 2 OH⁻ (aq) → 2 H₂O (l) + Ba²⁺ (aq) + 2I⁻ (aq)