Ask Question
1 May, 22:26

What is the [OH-] in a solution

with a POH of 7.86?

[OH-] = [?] x 10?!)

+3
Answers (1)
  1. 2 May, 01:53
    0
    1.380 * 10^-8 M

    Explanation:

    The pH is the measure of alkalinity or acidity of a substance.

    It is the negative logarithm of H + ions concentration [H+].

    pH = - log[H+]

    pOH on the other hand is negative logarith of OH - concentration [OH-].

    pOH = - log[OH-]

    In this case;

    pOH = 7.86

    We can calculate the [OH-]

    pOH = - log[OH-]

    But, pOH = 7.86

    pOH = - log[OH-]

    -log[OH-] = 7.86

    [OH-] = Antilog - 7.86

    = 1.380 * 10^-8 M

    Therefore, [OH-] is 1.380 * 10^-8 M
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the [OH-] in a solution with a POH of 7.86? [OH-] = [?] x 10?!) ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers