Ask Question
28 August, 18:56

If 39.0 g of C6H6 reacts with excess chlorine and produces 30.0 g of C6H5Cl in the reaction C6H6 + Cl2 → C6H5Cl + HCl, what is the percent yield of C6H5Cl?

+2
Answers (1)
  1. 28 August, 20:46
    0
    53.4 % is the percent yield

    Explanation:

    This is the reaction:

    C₆H₆ + Cl₂ → C₆H₅Cl + HCl

    First of all we need to know the moles of benzene we used

    39 g. 1 mol / 78 g = 0.5 moles

    Ratio is 1:1 so 1 mol of benzene produces 1 mol of chloride

    0.5 moles of chloride were produced by 0.5 moles of benzene

    We must calculate the mass of chloride we produced

    0.5 mol. 112.45 g / 1 mol = 56.2g

    Let's calculate the percent yield

    (Yield produced / Theoretical yield). 100

    (30 g / 56.2 g). 100 = 53.4 %
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If 39.0 g of C6H6 reacts with excess chlorine and produces 30.0 g of C6H5Cl in the reaction C6H6 + Cl2 → C6H5Cl + HCl, what is the percent ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers