The natural gas in a 30-L NGV fuel tank has a pressure of 2.05 * 10^4 kPa at a temperature of 297 K. How many kilograms of fuel are in the tank

4727.2 * 10³ Kg

Explanation:

Given dа ta:

Pressure of gas = 2.05 * 10⁴ KPa (202.32 atm)

Temperature = 297 K

Volume = 30 L

Mass of fuel = ?

Solution:

Molar mass of gas is missing. It is 19 g/mol.

Formula:

PV = nRT

n = PV/RT

n = 202.32 atm * 30 L / 0.0821 atm. L. mol⁻¹. k⁻¹ * 297 K

n = 6069.6 atm. L / 24.4 atm. L. mol⁻¹

n = 248.8 mol

Mass:

Number of moles = mass / molar mass

Mass = number of moles * molar mass

Mass = 248.8 mol * 19 g/mol

Mass = 4727.2 g

In kilogram:

4727.2 g / 1 g * 1000 Kg

4727.2 * 10³ Kg