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28 January, 17:02

calculate the enthalpy change for converting 1.00 mol of liquid water at 100 C to water vapor at 145 degree celsius for water Δ H vaporization=40.7kj/mol and the specfic heat of water vapor is 1.84j/g-K

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  1. 28 January, 17:18
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    q1 = mCpΔT

    = 18.016g * 1.84J/g. K * (418.15-373.15)

    = 1491.72 J

    q2 = n*ΔH vap

    = 1mol * 44.0kJ/mol

    = 44KJ

    ∴ qtotal = q1 + q2

    = 1.498kJ + 44.0kJ

    = 45.498KJ

    Explanation: The heat flow can be separated into steps. all that is being observed at a constant pressure, the heat flow is equal to the enthalpy.
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