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25 June, 06:57

Two different proteins X and Y are dissolved in aqueous solution at 37 ∘C. The proteins bind in a 1:1 ratio to form XY. A solution that is initially 1.00 mM in each protein is allowed to reach equilibrium. At equilibrium, 0.23 mM of free X and 0.23 mM of free Y remain. What is Kc for the reaction?

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  1. 25 June, 08:52
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    Kc = 1.4556 * 104

    Explanation:

    Two different proteins X and Y will bind in a 1:1 ratio to form XY

    X + Y ⇔ XY

    This means that for 1 mole X consumed, there will be 1 mole of Y consumed and 1 mole of XY produced

    Both proteins X and Y have initially 1mM ( = 0.001M)

    if there is consumed x moles of protein X then there will also be consumed x moles of protein Y. As given the remaining concentration of both proteins X and Y is 0.23 mM ( = 0.23 * 10^-3 M).

    This means also that here will be produced x of the protein XY

    x = 10^-3 - 0.23*10-3 = 7.7 * 10^-4 M

    Kc = [XY] / [X][Y]

    Kc = 7.7 * 10^-4 / ((0.23 * 10^-3) * (0.23 * 10^-3))

    Kc = 1.4556 * 104
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