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24 July, 19:11

How mamy moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess

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  1. 24 July, 21:21
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    3.62moles

    Explanation:

    First let us generate a balanced equation for the reaction

    2Na + Cl2 - > 2NaCl

    Molar Mass of Na = 23g/mol

    Mass of Na from the balanced equation = 2 x 23 = 46g

    Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

    Mass of NaCl from the balanced equation = 2 x 58.5 = 117g

    From the question,

    46g of Na produced 117g of NaCl.

    Therefore, 83g of Na will produce = (83 x 117) / 46 = 211.11g of NaCl

    Converting this mass (211.11g of NaCl) to mole, we obtain:

    n = Mass / Molar Mass

    n = 211.11 / 58.5

    3.62moles
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