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8 April, 04:42

N2+3H2-2NH3

calculate the number of grams of NH3 are formed when 3.0 mole of N2 is reacted with 6.7 moles of H2

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  1. 8 April, 06:55
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    102 grams of ammonia is formed when 3 moles of nitrogen and 6.7 moles of hydrogen reacts.

    Explanation:

    The equation given is of Haeber's process in which the nitrogen is limiting factor in the ammonia formation and hydrogen if in excess gets delimited.

    We know that 1 mole of Nitrogen gives 2 moles of ammonia.

    We have 3 moles of nitrogen here,

    So, 6 moles of ammonia will be form

    so from the formula

    no of moles=mass/atomic mass

    mass = no. of moles*atomic mass

    = 6*17

    = 102 grams of ammonia will be formed.

    So, 6 moles or 102 grams of ammonia is formed when 3 mole of nitrogen and 6.7 mole of hydrogen reacts.
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