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24 September, 14:31

The stepwise formation constants for complexes of NH3 with [Cu (OH2) 6]2 + (aq) are logK11 = 4.15, log K12 = 3.50, log K13 = 2.89, log K14 = 2.13, log K15 = - 0.52. Suggest a reason why Kt5 is so different? (10)

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  1. 24 September, 15:21
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    K₅ is smaller because the reaction is slower due to steric and electronic effects.

    Explanation:

    K is the rate constant of the reaction. The higher the value of log K, the higher the value of K and the faster is the reaction.

    The reaction can be represented by the following reaction:

    6 NH₃ + [Cu (OH₂) ₆]²⁺ → [Cu (NH₃) ₆]²⁺ + 6 H₂O

    This means that the reaction is exchanging the H₂O ligands by NH₃ ligands.

    The more NH₃ ligands we add to the complex, the more difficult (slower) is the substitution. This happend because the addition of NH₃ ligands promotes a steric hindrance and electronic repulsion, which makes it harder for the next NH₃ to approach the complex and substitute the H₂O ligand.

    This is the reason why K₅ is negative. The rate of this substitution is extremelhy low.
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