Ask Question
19 February, 18:58

Predict the reactants of this chemical reaction. That is, fill in the left side of the chemical equation. Be sure the equation you submit is balanced. (You can edit both sides of the equation to balance it, if you need to.) Note: you are writing the molecular, and not the net ionic equation. CaCl2 (aq) + H20 (I)

+2
Answers (2)
  1. 19 February, 20:10
    0
    CaCl₂ (aq) + 2H₂O (I) → Ca (OH) ₂ (aq) + 2HCl (g)

    Explanation:

    The reactants are:

    CaCl₂ and water (H₂O)

    The products are:

    HCl and Ca (OH) ₂

    The balanced equation is: CaCl₂ (aq) + 2H₂O (I) → Ca (OH) ₂ (aq) + 2HCl (g)

    1 mol of calcium chloride reacts with 2 moles of water, in order to produce calcium hydroxide and 2 moles of hydrogen chloride.
  2. 19 February, 20:16
    0
    The reactants are Ca (OH) 2 (s) and HCl (aq)

    The balanced equation is

    Ca (OH) 2 (s) + 2HCl (aq) → CaCl2 (aq) + 2H20 (I)

    Explanation:

    Step 1: Data given

    The products of the equation are: CaCl2 (aq) + H20 (I)

    Step 2: The unbalanced equation

    Ca^2 + (aq) + 2Cl - (aq) + H + (aq) + OH - (aq) → CaCl2 (aq) + H20 (I)

    Ca (OH) 2 (s) + HCl (aq) → CaCl2 (aq) + H20 (I)

    Balancing the equation

    Ca (OH) 2 (s) + HCl (aq) → CaCl2 (aq) + H20 (I)

    On the left side we have 1x H, on the right side we have 2x H (in H2O). To balance the amount of H on both sides, we have to multiply HCl by 2.

    When we multiply HCl by 2, the amount of Cl on both sides is also balanced. Now the equation is balanced.

    Ca (OH) 2 (s) + 2HCl (aq) → CaCl2 (aq) + 2H20 (I)

    The reactants are Ca (OH) 2 (s) and HCl (aq)

    The balanced equation is

    Ca (OH) 2 (s) + 2HCl (aq) → CaCl2 (aq) + 2H20 (I)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Predict the reactants of this chemical reaction. That is, fill in the left side of the chemical equation. Be sure the equation you submit ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers