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23 December, 05:35

Write and balance the combination reaction for the heating of solid magnesium in the presence of nitrogen gas. In a particular experiment, a 9.27-g sample of N2 completely reacts. What is the mass of magnesium must have been consumed during the reaction if the reaction yield is 100%?

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  1. 23 December, 07:07
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    The mass of magnesium that has been consumed, was 6.69 g

    Explanation:

    The reaction is this one:

    3Mg (s) + N₂ (g) → Mg₃N₂

    3 moles of solid magnesium react with 1 mol of nitrogen, to make 1 mol of magnesium nitride.

    If 9.27 grams of nitrogen react, we see that ratio is 1:1, so we make 9.27 grams of nitride.

    Mass / Molar mass = Moles

    9.27 g / 100.9 g/m = 0.092 moles

    If we have 0.092 moles of nitride, ratio between Mg is 1:3 so, the rule of three will be:

    1 mol of Nitride was produced by 3 moles of Mg (s)

    0.092 moles of nitride were produced by, (0.092.3) / 1 = 0.275 moles

    Mass og Mg = 24.3 g/m

    Molar mass. Moles = Mass

    0.275 m. 24.3g/m = 6.69 g
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