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Chemistry
Cadence
13 September, 03:23
What mass will 2.5 L of chlorine gas be at STP?
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Jacey Simpson
13 September, 06:27
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One mole of any gas at STP takes up 22.4 L
1 mole of gas = 22.4L
2.5 moles of gas takes up = (22.4 L / 1 mole) x 2.5 mole
= 56 L
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Francisco Howell
13 September, 06:32
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Answer: m = 7.7 g Cl2
Explanation: To find mass of chlorine gas we will first derive the ideal gas law formula and find first the number of moles of Cl2. At STP, Pressure is equal to 1 atm and temperature is 273 K.
n = PV / RT
= 1 atm (2.5 L) / 0.0821 L. atm / mole. K (273 K)
= 0.11 mole Cl2
Convert moles of Cl2 to grams using the molar mass of Cl2 which is 70 g Cl2.
0.11 mole Cl2 x 70 g Cl2 / 1 mole Cl2
= 7.7 g Cl2
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