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13 April, 06:36

Three solutions 39.0 mL of 0.2 M KNO₃; 59.0 mL of 0.9 M Ca (NO₃) ₂; and 63.0 mL of 0.345 M KCl were poured together to make one new solution. What is the concentration of Cl⁻ after mixing? Answer in units of mol/L.

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  1. 13 April, 09:07
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    [Cl⁻] = 0.135 M

    Explanation:

    The concentration of Cl⁻ is equal to the total moles of Cl⁻ divided by the total volume:

    C = n/V

    All of the moles of Cl⁻ come from dissociation of the KCl:

    KCl ⇒ K⁺ + Cl⁻

    We will calculate the moles of Cl⁻ based on the amount of KCl added by using the molar ratio of 1:1.

    (0.345 mol/L) (63.0 mL) = (21.735 mmol KCl) (Cl⁻/KCl) = 21.735 mmol Cl⁻

    Extra significant figure are kept to avoid round-off errors.

    Now we can calculate the total volume, which is the sum of the volume of the three solutions added:

    (39.0 mL) + (59.0 mL) + (63.0 mL) = 161.0 mL

    Finally, we calculate the concentration of Cl⁻

    [Cl⁻] = (21.735 mmol) / (161.0 mL) = 0.135 M
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