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27 May, 09:39

The molar solubility of Ag2CO3 is 0.074M at 10°C.

What is the Ksp of Ag2CO3 at the same degree?

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  1. 27 May, 10:17
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    0.00162 is the Ksp of Ag2CO3 at 10 degrees.

    Explanation:

    Ag2CO3 (s) - - - 2Ag + (aq) + CO3 ^-2 (aq)

    The product of molar solubility of each ion in moles/litre gives the solubility product.

    The molar solubility of Ag2CO3 is 0.074 M at 10 degrees.

    From the above reaction we can see that

    2 Moles of Ag and 1 mole of carbonate ions,

    So, [Ag2CO3] = 2[Ag]^2[CO3^2-]

    Ksp of Ag + = 2*0.074

    = 0.148

    Ksp of CO3^-2 = 0.074

    = 0.148

    Ksp of AgNO3 = [0.148]^2 [0.074]

    Ksp of AgNO3 = 0.00162 AT 10 degrees
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