What is the molarity of the solution resulting from the dissolution of 239 g glucose (C6H12O6) in 250

mL water?

Molarity = 5.32 M

Explanation:

Given dа ta:

Mass of glucose = 239 g

Volume = 250 mL (250 / 1000 = 0.25 L)

Molarity = ?

Solution;

Formula:

Molarity = number of moles / volume in litter

Number of moles:

Number of moles = mass / molar mass

Number of moles = 239 g / 180.2 g/mol

Number of moles = 1.33 mol

Molarity:

Molarity = number of moles / volume in litter

Molarity = 1.33 mol / 0.25 L

Molarity = 5.32 M