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30 June, 08:22

The specific heat of a certain type of metal is 0.128J / (g.°C). What is the final temperature if 305 J of hear is added to 28.8 g of this metal, initially at 20.0°C?

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  1. 30 June, 10:59
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    Answer: Temperature final = 103 °C

    Explanation: To solve for final temperature we use the equation of heat:

    Q = mc∆T

    Next derive the equation to find final temperature

    Q = mc (T final - T initial)

    Q / mc = T final - T initial

    Transpose T initial and change the sign so that T final will be left.

    T final = Q / mc + T initial

    Substitute the values:

    T final = 305 J / 28.8 g x 0.128 J / (g°C)

    = 305 J / 3.6864 J/°C

    = 82.7 + 20.0°C

    = 103 °C final temperature.
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