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19 March, 23:10

A 280. L kiln is used for vitrifying ceramics. It is currently operating at 915 ∘C, and the pressure is 1.075 atm. How many moles of air molecules are within the confines of the kiln?

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  1. 20 March, 02:38
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    3.0857 moles of air

    Explanation:

    For this situation, we will use the ideal gas wet: PV = nRT

    ⇒ with P = pressure (in atm)

    ⇒ with V = volume (in liter)

    ⇒ with n = number of moles of gas

    ⇒ with R = the ideal gas constant = 0.0821 L * atm * K^-1 * mol^-1

    ⇒ with T = the absolute temperature (in Kelvin)

    ⇒ 915 °C = 915 + 273.15 K = 1188.15 K

    To calculate the number of moles of air we have to distort the formule:

    n = (P*V) / (R*T) = (1.075 atm * 280 L) / (0.0821 L * atm * K^-1 * mol^-1 * 1188.15 K)

    n = 3.0857 moles of air
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