Ask Question
12 May, 11:52

If you want to prepare 0.50 liters of a 0.35 M solution of NaNO3, how many grams of the salt should

you weigh out?

+3
Answers (1)
  1. 12 May, 14:31
    0
    14.87 g

    Explanation: Molarity refers to the concentration of a solution in moles per liter. It is calculated by dividing the number of moles of solute and the volume of the solution.

    We are given;

    Volume as 0.5 liters

    Molarity as 0.35 M

    We are required to calculate the mass of the solute NaNO₃

    Step 1 : Find the number of moles of the solute NaNO₃

    Moles = Molarity * Volume

    Moles = 0.35 M * 0.5 L

    = 0.175 moles

    Step 2: Mass of the solute NaNO₃

    Mass is calculated by multiplying the number of moles by the molar mass of the compound.

    Molar mass of NaNO₃ = 84.9947 g/mol

    Therefore;

    Mass of NaNO₃ = 0.175 moles * 84.9947 g/mol

    = 14.874 g

    = 14.87 g

    Thus, the mass of the salt solute is 14.87 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If you want to prepare 0.50 liters of a 0.35 M solution of NaNO3, how many grams of the salt should you weigh out? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers