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28 August, 09:52

At a certain temperature the vapor pressure of pure heptane C7H16 is measured to be 454. mmHg. Suppose a solution is prepared by mixing 102. g of heptane and 135. g of chloroform CHCl3.

Calculate the partial pressure of heptane vapor above this solution. Be sure your answer has the correct number of significant digits.

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  1. 28 August, 11:59
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    Mass of heptane = 102g

    Vapor pressure of heptane = 454mmHg

    Molar mass of heptane = 100.21

    No of mole of heptane = mass/molar mass = 102/100.21

    No of mole of heptane = 1.0179

    Therefore the partial pressure of heptane = no of mole heptane * Vapor pressure of heptane

    Partial pressure of heptane = 1.0179*454mmHg

    Partial pressure of heptane = 462.1096 = 462mmHg

    the partial pressure of heptane vapor above this solution = 462mmHg
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