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8 August, 13:17

You have a total body concentration of 300 mOsM and total body volume of 3 liters. If you add 0.5 L of a solution containing 150 mosmol of NaCl to the body, what would the new total body concentration be?

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  1. 8 August, 15:27
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    The new total body concentration would be 300 mOsM

    Explanation:

    In order to do this, we need to convert all concentrations to moles.

    First, with the total body concentration, we have the initial volume of 3 liters and the concentration of 300 M (I will omit til the end the part of mOs)

    The moles of the body concentration in this volume is:

    moles = M * V

    moles = 300 * 3 = 900 moles

    To this moles, we add 150 moles of NaCL so, the total moles now is:

    moles = 900 + 150 = 1050 moles

    Finally, we can calculate the concentration with the new volume of 3.5 L (the sum of 3 and 0.5 liters added):

    M = 1050 / 3.5

    M = 300 mOsM

    So the concentration remains the same as initial
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