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15 May, 16:07

What volume of carbon monoxide is required to react with 32.5 liters of oxygen gas according to the following reaction? (All gases are at the same temperature and pressure.)

carbon monoxide (g) + oxygen (g) carbon dioxide (g)

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  1. 15 May, 17:59
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    65 L is the volume of CO required

    Explanation:

    This is the reaction:

    2CO (g) + O₂ (g) → 2CO₂ (g)

    We must work with density to solve this problem

    Density = Mass / volume

    Let's determine the moles of O₂

    1.43 g/mL = mass / 32500 mL

    Notice, that we had to convert the volume from L, to mL, because the units of density.

    Mass of O₂ → 1.43 g/mL. 32500 mL = 46475 g

    Let's convert the mass to moles (mass / molar mas)

    46475 g / 32 g/mol = 1452.3 moles

    So ratio is 1:2

    1 mol of oxygen needs 2 moles of CO, to react

    Then, 1452.3 moles of O₂ would need the double of CO to react

    1452.3 moles. 2 = 2904.6 moles of CO

    This moles are contained in (mol. molar mass) =

    2904.6 mol. 28 g/mol = 81328.8 g

    Density of CO = Mass of CO / Volume of CO

    1.25 g/mL = 81328.8 g / Volume of CO

    81328.8 g / 1.25 g/mL = 65063 mL

    If we convert to L

    65063 mL = 65.0 L
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