Ask Question
28 September, 20:08

A balloon of helium was put in the freezer at - 23°C. Its volume at this temperature was 2.5 liters. It was removed from the freezer. Eventually, it reached a temperature of 177°C. What would its volume be at this temperature? (Neglect any force used to stretch the rubber balloon.) (1.) 45000 (2.) 0.22 (3.) 4.5 (4.) 1.4

+2
Answers (1)
  1. 28 September, 20:20
    0
    4.5 L

    Explanation:

    We will use the combined gas law formula;

    P₁V₁/T₁ = P₂V₂/T₂

    Because the pressure remains the same, it cancels out and what remains is;

    V₁/T₁ = V₂/T₂

    Before evaluating remember to change the temperatures into Kelvin;

    -23° = 250.15 K

    177° = 450.15 K

    We replace the variables with known values;

    2.5 / 250.15 = V₂ / 450.15

    V₂ = 2.5 / 250.15 * 450.15

    V₂ = 4.4988 L

    ≅ 4.5 L
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A balloon of helium was put in the freezer at - 23°C. Its volume at this temperature was 2.5 liters. It was removed from the freezer. ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers