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31 August, 14:10

5.00 g of an unknown compound was dissolved in 250.0 mL of water. The unknown compound was found to be a non-electrolyte and the osmotic pressure of the solution was determined to 14.5 atm at 298 K. Calculate the molar mass of the unknown compound (in units of g/mol). R = 0.08206 (L atm) / (mol K)

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  1. 31 August, 14:48
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    This unknown compound has a molar mass of 33.74g/mole

    Explanation:

    Step 1: Given data

    The formula for the osmotic pressure is:

    π = MRT = 14.5 atm

    ⇒ with M = Concentration of the solution

    ⇒ with R = gas constant = 0.08206 L atm / mol K

    ⇒ with T = absolute temperature (in Kelvin) = 298K

    Step 2: Calculate concentration

    M = π / RT

    M = 14.5 / (0.08206 * 298)

    M = 0.593 M this is 0.593 moles per L

    Step 3: Calculate number of moles

    Since the volume is only 0.250 L, the amount of moles is:

    0.593 * 0.250 L = 0.1482 moles

    Step 4: Calculate molar mass

    The molar mass is : mass / moles

    Molar mass of this unknown compund = 5g / 0.1482 moles = 33.74 g/mole

    This unknown compound has a molar mass of 33.74g / mole
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