What is the minimum number of moles of sodium borohydride required to fully reduce 0.55 grams of benzophenone? Enter only the number with two significant figures.

see explanation below

Explanation:

In this case, is pretty easy. This is a reduction reaction to form the respective alcohol.

Now for each mole of benzophenone that it's present, reacts with 1 mole of Sodium borohydryde, so, all we need to do, is to calculate the moles of benzophenone presents and these, would be the same moles of NaBH4 so:

moles Benzophenone : m/MM

The molar mass of benzophenone reported is 182.22 g/mol so:

moles Benzophenone = 0.55/182.22 = 3.02x10⁻³ moles

so the moles of NaBH₄ = 3.02x10⁻³ moles