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21 August, 16:16

A gas currently has a pressure of 17 atm, a volume of 96 L, and a temperature of 284 K. If its initial

pressure was 16 atm and initial volume was 84 L, what was the initial temperature?

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  1. 21 August, 17:28
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    The initial temperature was 234K

    Explanation:

    We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T

    (P1xV1) / T1 = (P2xV2) / T2

    (16atmx84L) / T1 = (17atmx 96 L) / 284K

    1344atmx L/T1 = 5,75 atm x L/K

    T1 = 1344atmx L/5,75 atm x L/K = 233,74K
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