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6 December, 09:47

Three moles of neon expand isothermally from 0.153 m3 to 0.319 m3 while 4.86 * 103 J of heat flows into the gas. Assuming that neon is an ideal gas, find its temperature.

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  1. 6 December, 10:21
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    T = 265 degree

    Explanation:

    Given. n = 3

    Vf = 0.319m3.

    Vi = 0.153m3.

    Q = 4.86*10^3 J

    For external process, change in internal energy is zero

    W = Q = 4.86*10^3

    Also work done for isothermal process is given by

    W = nRT in (vf/vi)

    T = w/nR in (vf/vi)

    T = 4.86*10^3/3*8.314in (0.319/0.153)

    T = 265degree
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