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14 September, 19:31

What is the maximum mass of ethyl alcohol you could boil with 2000 JJ of heat, starting from 17 ∘C∘C?

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  1. 14 September, 21:19
    0
    maximum mass C2H5OH = 13.398 g

    Explanation:

    Q = mCpΔT

    ∴ Q = 2000 J

    ∴ Cp C2H5OH = 112.0 J/mol. K

    ∴ T1 = 17°C = 290 K

    ∴ T2 = Tboil C2H5OH = 78.4°C = 351.4 K

    ⇒ ΔT = 351.4 K - 290 K = 61.4 K

    ∴ m = Q/CpΔT

    ⇒ mol C2H5OH = (2000 J) / ((112.0 J/mol. K) (61.4 K)) = 0.29083 mol

    ∴ mm C2H5OH = 46.07 g/mol

    ⇒ mass C2H5OH = (0.29083 mol) * (46.07 g/mol) = 13.398 g
  2. 14 September, 23:22
    0
    Answer: Q=mcΔT

    Explanation:

    c ethyl alcohol = 2400 J / (kg*K)

    T boil ethyl alcohol = 78 C = 351 K

    T starting = 17 C = 290 K

    m=Q / (c*ΔT)

    m = (2400 J) / [ (2400 J/kg*K) (351 K - 290 K) ]

    = 0.0028g
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