A balloon is filled with 35.0 L of helium in the morning when the temperature is 20.0C. By noon the temperature has risen to 45.0C. What is the new volume of the balloon?

A

2.5L

B

3.5L

C

4.5L

D

5.5L

The question to your answer is: V2 = 78.75 l non if the options given

Explanation:

Data

V1 = 35 l

T1 = 20 °C

T2 = 45°C

V2 = ?

Formula

V1 / T1 = V2 / T2

Clear V2 from the equation

V2 = V1T2/T1

Substitution

V2 = (35) (45) / (20)

V2 = 78.75 l

The new volume of the balloon is 78.75 L

Explanation:

Charles's law relates the volume and temperature of an ideal gas, to a constant pressure, therefore we must use that ratio to calculate the final temperature, according to the data provided:

Vinitial = 35 L

Tinitial = 20ºC

Vfinal = ?

Tfinal = 45ºC

Vfinal = (Vinitial x Tfinal) / Tinitial = (35 L x 45ºC) / 20ºC = 78.75 L