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15 February, 10:42

What is the silver concentration in a solution prepared by mixing 250

mL of 0.310 M silver nitrate with 100 mL of 0.160 M of sodium chromate?

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Answers (1)
  1. 15 February, 13:01
    0
    0.221M

    Explanation:

    From the question,

    The Molarity of AgNO₂ = 0.310 M

    Hence, the concentration of Ag⁺ = 0.301 M

    The volume of AgNO₂ = 250 mL

    and,

    The Molarity of Sodium chromate = 0.160 M

    The volume of Sodium chromate = 100 mL.

    As the solution is mixed the final volume becomes,

    250mL + 100mL = 350mL

    Now, using the formula, to find the final molarity of the mixture,

    M₁V₁ (initial) = M₂V₂ (final)

    substituting the values, in the above equation,

    0.310M * 250ml = M₂ * 350ml

    M₂ = 0.221M

    Hence, the concentration of the silver in the final solution = 0.221M
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