Ask Question
21 July, 09:21

A 75 g piece of gold (Au) at 1000 K is dropped into 200 g of H2O at 300K in an insulated container at 1 bar. Calculate the temperature of the system once the equilibrium has been reached. Assume that CP, m for Au and H2O are constant and its value for 298 K throughout the temperature range of interest.

+3
Answers (1)
  1. 21 July, 11:02
    0
    The temperature of the system once the equilibrium has been reached = 372.55K

    Explanation:

    Heat capacity of gold = 129 J/Kg*c.

    Heat capacity of water

    4,184 J/Kg*c.

    Mass of gold = 75g = 0.075Kg

    Mass of water = 200g = 0.2Kg

    From conservation of energy

    m1*C1 * (t11 - t2) = m2*C2 * (t2 - t21)

    Substituting we have

    0.075 * 129 * (1000-t2) = 0.2 * 4184 * (t2 - 300) = solving for t2, we have

    933.55*t2 = 347790

    or t2 = 372.55K

    The temperature of the system once the equilibrium has been reached = 372.55K
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 75 g piece of gold (Au) at 1000 K is dropped into 200 g of H2O at 300K in an insulated container at 1 bar. Calculate the temperature of ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers