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4 April, 15:43

What would be the saturation concentration (mole/L) of oxygen (O2) in a river in winter when the air temperature is 0°C if the Henry's law constant at this temperature is 2.28 * 10-3 mole/L-atm? What would the answer be in units of mg/L?

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  1. 4 April, 17:38
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    20.21*10^-4 mg/L is the concentration.

    Explanation:

    Given:

    Pressure=1 atm.

    Temperature = 0 degrees

    Volume percent of air is 21%

    Henry's Law constant K = 2.28 x 10^-3 mole/L-atm

    The partial pressure of oxygen is 0.21 atm.

    By Henry's law:

    Concentration = K X Partial pressure

    = 2.28*10^-3 * 0.21

    = 4.79*10^-4 moles/litre

    Since, at STP 1 mole of oxygen occupies volume of 22.4L

    concentration = mass/volume

    mass = 4.79*10^-4-4*22.4

    = 20.21*10^-4 mg

    20.21*10^-4 mg/L is the concentration.
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