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23 May, 03:32

If a substance increases the OH - concentration of pure water by 10^4. what is the pH of the solution?

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  1. 23 May, 04:38
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    pH = 11

    Explanation:

    The concentration of OH⁻ in pure water is 10⁻⁷ M. If a substance increases OH⁻ concentration by 10⁴, the new concentration will be:

    [OH⁻] = 10⁴ x 10⁻⁷ M = 10⁻³M

    We can calculate pOH using it's definition:

    pOH = - log[OH⁻] = - log (10⁻³) = 3

    Then, we can find out pH using the following relation:

    pH + pOH = 14

    pH = 14 - pOH = 14 - 3 = 11

    Since pH = 11 is higher than 7, we can confirm that the substance is a base.
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