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10 January, 02:00

How much CrCl3 • 6H20 is needed to prepare 1 L of solution containing 20.0g Cr3 + per L?

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  1. 10 January, 05:18
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    salt mass=102.5gCrCl3.6H2O

    Explanation:

    Hello!

    To know how much CrCl3.6H2O we need, we follow the steps below

    First we have to know what the mass of the compound is

    Cr = 52g / mol

    Cl = 35.5g / mol

    H = 1g / mol

    O = 16g / mol

    We calculate the mass

    52 + (35.5 * 3) + 6 * (2 * 1 + 16) = 266.5g

    We have 20g Cr, so we calculate the amount of salt:

    20gCr * (266.5g salt / 52gCr) = 102.5gCrCl3.6H2O

    salt mass=102.5gCrCl3.6H2O
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