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17 May, 09:25

If 1.72 mol of ZnS is heated in the presence of 3.04 mol pf O2, which is the limiting reactant?

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  1. 17 May, 12:31
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    The limiting reactant is the ZnS

    Explanation:

    The equation for this reaction is:

    2 ZnS + 3O₂ = 2 ZnO + 2 SO₂

    2 moles of zinc sulfure reacts with 3 moles of oxygen.

    Then, 1.72 mol of ZnS would react with (1.72.3) / 2 = 2.58 moles of O₂

    If we have 3.04 moles, then the oxygen is the reactant in excess.

    Let's confirm, the ZnS as the limiting reactant.

    3 moles of oxygen react with 2 moles of sulfure.

    Then, 3.04 moles of O₂ would react with (3.04.2) / 3 = 2.02 moles of ZnS

    We have 1.72 moles of Zn S and it is not enough for the 2.02 moles that we need, for the reaction.
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