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20 July, 08:28

The vapor pressure of pure ethylene dibromide is 172 Torr and that of pure propylene dibromide is 128 Torr both at 358 K and 1 atm pressure. If these two components follow Raoult's law, estimate the total pressure in kPa and the vapor composition in equilibrium with a solution that is 0.600 mol fraction propylene dibromide.

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  1. 20 July, 10:15
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    A) PT (Total Pressure) = 19.41 Kpa B) composition in equilibrium: X ED = 0.47 (ED: ethylene dibromide), X PD = 0.53 (PD: propylene dibromide)

    Explanation:

    Part A) dа ta: P ED = 172 Torr = 22931.04 Pa, P PD = 128 Torr = 17064.96 Pa, X PD = 0.600

    Where: P ED = vapor pressure of pure ethylene dibromide

    P PD = vapor pressure of pure propylene dibromide

    We can use then Raoult's Law:

    PT = P ED*X ED + P PD*X PD

    PT = total pressure

    X ED = mol fraction of ethylene dibromide in solution

    X PD = mol fraction of propylene dibromide in solution

    Also, we can considere that: 1 = X ED + X PD, then X ED = 1 - 0.600 = 0.400

    PT = 22931.04Pa * (1 - 0.600) + 17064.96Pa*0.600

    PT = 19411.39 Pa = 19.41 KPa

    Part B) We cna use the following formula to determine the vapor composition (mol fraction) of each component

    X i = (Y i*PT) / Pi

    Where:

    X i = mol fraction of component i in solution

    Y i = mol fraction of component i in vapor phase

    PT = total pressure

    P i = Vapor pressure of component i

    Y i = (X i * Pi) / PT

    Y DE = [ (1 - 0.600) * 22931.04Pa]/19411.30 Pa

    Y DE = 0.47 mol fraction of ethylene dibromide in vapor phase

    Y PD = (0.600*17064.96 Pa) / 19411.39 Pa

    Y PD = 0.53 mol fraction of propylene dibromide in vapor phase
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