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22 January, 23:02

Which sample contains the greater number of atoms, a sample of Li that contains 6.8 x 10^22 atoms or a 1.97 mole sample of Na?

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  1. 22 January, 23:25
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    1.97 moles of Na contains greater number of atoms than 6.8 * 10²² atoms of Li.

    Explanation:

    To solve this problem we will first calculate the number of atoms contained by 1.97 moles of Na and then will compare it with 6.8 * 10²² atoms of Li.

    As we know that 1 mole of any substance contains exactly 6.022 * 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of atoms contained by 1.97 moles of Na, we will use following relation,

    Moles = Number of Atoms : 6.022 * 10²³ atoms. mol⁻¹

    Solving for Number of Atoms,

    Number of Atoms = Moles * 6.022 * 10²³ Atoms. mol⁻¹

    Putting values,

    Number of Atoms = 1.07 mol * 6.022 * 10²³ Atoms. mol⁻¹

    Number of Atoms = 1.18 * 10²⁴ Atoms of Na

    Hence,

    1.97 moles of Na contains greater number of atoms than 6.8 * 10²² atoms of Li.
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