Which sample contains the greater number of atoms, a sample of Li that contains 6.8 x 10^22 atoms or a 1.97 mole sample of Na?

1.97 moles of Na contains greater number of atoms than 6.8 * 10²² atoms of Li.

Explanation:

To solve this problem we will first calculate the number of atoms contained by 1.97 moles of Na and then will compare it with 6.8 * 10²² atoms of Li.

As we know that 1 mole of any substance contains exactly 6.022 * 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of atoms contained by 1.97 moles of Na, we will use following relation,

Moles = Number of Atoms : 6.022 * 10²³ atoms. mol⁻¹

Solving for Number of Atoms,

Number of Atoms = Moles * 6.022 * 10²³ Atoms. mol⁻¹

Putting values,

Number of Atoms = 1.07 mol * 6.022 * 10²³ Atoms. mol⁻¹

Number of Atoms = 1.18 * 10²⁴ Atoms of Na

Hence,

1.97 moles of Na contains greater number of atoms than 6.8 * 10²² atoms of Li.