Calculate the volume in liters of a 0.360 mol/l barium acetate solution that contains 100. g of barium acetate (Ba (C2H3O2) 2). Round your answer to 3 significant digits.

1.08 liters is the volume of 100 g of Ba (CH₃COO) ₂

Explanation:

This data is a sort of concentration (Molarity) → 0.360 M [Ba (CH₃COO) ₂]

It means that 0.36 moles of solute are contained in 1L of solution.

We should determine the moles of salt, that corresponds to 100 g of solute.

Mass / Molar mass

Ba (CH₃COO) ₂ molar mass = 255.3 g/m

100 g / 255.3 g/m = 0.391 moles

So, we can apply a rule of three to calculate the volume of salt.

0.360 moles of solute are contained in 1L of solution

0.391 would be contained in (0.391.1) / 0.360 = 1.08 liters