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23 January, 04:37

Barium has a body-centered cubic structure. If the atomic radius of barium is 222 pm, calculate the density of solid barium?

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  1. 23 January, 07:02
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    Answer: density = 3.377g/cm³

    Explanation:

    Density = (molecular weight * effective number of atoms per unit cell) / (volume of unit cell * avogadro constant)

    D = (M * n) / (V*A)

    M = 137g/mol

    n = 2 (For BCC)

    V=a³, where a = 4r/√3

    a = (4*222) / √3

    a=512.69pm

    a = 512.69*10^-10cm

    V = (512.69*10^-10) ^3

    V = 1.3476*10^-22cm³

    D = (137*2) / (1.3476*10^-22 * 6.02^23)

    D = 3.377g/cm³

    Therefore the density of barium is 3.377g/cm³
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